What is the equation for a line passing through point 36 and

What is the equation for a line passing through point (-3,6) and perpendicular to the equation y=1/3x+4?

We have given y=1/3x+4

compare it with y= mx+b , we have slope = 1/3

Let the slope of required line = m

Now we know that the product of slopes of perpendicular lines = -1

hence 1/3 * m = -1

=> m= -3

Equation of the line is

y-y1 = m(x-x1)

=> y- 6 = -3(x+3)

=> y- 6 = -3x -9

=> y= -3x -3