The following reaction takes place at a certain elevated tem

The following reaction takes place at a certain elevated temperature:

Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(s)

What is the percent yield of iron if 52.3 g Fe₂O₃ in excess CO produces 17.3 g Fe? The M.W. of Fe₂O₃ is 159.7 g/mol and the M.W. of CO is 28.01 g/mol.

Solution

52.3 g of Fe2O3 / 159.7 g/mol = 0.327 mole of Fe2O3

17.3 g of Fe / 55.847 g/mol = 0.309 mole of Fe

From the balaced Chemical equation

we say that the ->

1 mole Fe2O3 yields 2 mole Fe

0.327 mol Fe2O3 should yield 2x0.327 or 0.654 mol Fe

0.309 mole Fe yield / 0.5015 mole Fe theoretical = 0.6161 (61.61% yield)