The items on this review are represented of the herms sects

The items on this review are represented of the herms sects are allowed and calculating are not allowed on the calculator where working the items on this Find the SUM of the solution of the equation 4 x^2 + 20 x - 56 Use the Quadratic Formula to solve the equation 4n^2 - 6n -1 Choose the function that matches the graph Use the squareroot property to solve the equation (x - 6)^2 = 16 Find the SUM of the solutions of the equation 5x^2 + 3x - 2 =0 Find the product (4x - 5y)^2 Final the product (9p - 1)(81p^2 + 9p +1) Find the product (2r -3 times 2r + 3) Factor by grouping x^3 + 6x^2 + 8x + 48

Solution

4x2 +20x -56 = 0 or, x2 + 5x -14 = 0 or, x2 +7x-2x -14 = 0 or, x(x+7)-2(x+7) = 0 or, (x+7)(x-2) = 0. Thus x = -7 or, x = 2. The sum of the solutions of the given system is -7+2 = -5 2) 4n2=-6n-1 or, 4n2+6n+1= 0.On using the quadratic formula, we have n =[-6± { 62 -4*4*1}] /2*4 or, n = [ -6± (36-16)]/8 = (-6± 20)/8 = (-6± 25)/8 = (-3± 5)/4 . Thus, n = (-3+5)/4 or, n = (-3- 5)/4. The parabola shown in the graph opens upwards and has vertex at (-1,-9).Also, it passes through the point (2,0) Let its equation be f(x) = y = a(x+1)2 - 9. On substituting x = 2 and y = 0 in the equation, we get 0 = a( 2+1)2 -9 or 9a = 9 so that a = 1. Then the equation of the parabola is y = f(x) = (x+1)2 -9 = x2 +2x -8.The option C is the correct answer. (x-6)2 -16 = 0 or, (x-6)2 = 16 = 42. Hence, by the square root property, x-6 = ± 4. Thus x =6±4 i.e. x = 10 or, x = 2. 5x2+3x -2 = 0. On using the quadratic formula, we have x = [-3 ± {32-4*5*(-2)}]/2*5 =                    (-3± 49)/10 =( -3± 7)/10. Thus x = 4/10 = 2/5 or x = -10/10 = -1. he sum of the solutions is 2/5 -1   = -3/5. (4x-5y)2= (4x)2 -2(4x)(5y) +(5y)2 = 16x2-40xy+ 25y2 [ (a-b)2 = a2 -2ab+b2 ] Please post the remaining questions again.