A student working in a hybridoma lab mixes the spleen and th

A student working in a hybridoma lab mixes the spleen and the mycloma cells, in a 2:1 ratio, and resuspends the fused cells with 23 mL of HAT. He/she then adds 0.2 mL to all wells. What is the total number of cells per well?

Assume a concentration of 1.5•10^6 cells/mL for spleen and 1.0•10^6 cells/mL for mycloma cells.

Assume that there are 24 wells total.

Solution

2:1 ratio of spleen : myeloma cells.

So total cells will be 2(1.5* 10^6 ) + 1.0*10^6

= 3* 10^6 + 1*10^6

=4 *10^ 6 cells /3 ml ( 2ml from spleen + 1 ml from myeloma cells)

Add 23 ml of HAT, so that becomes 4*10^6 cells in 26 ml of HAT ( 3 ml + 23 ml = 26 ml)

26 ml contains 4*10^6 cells

1 ml will contain 4*10^6 /26 = 153846 cells

0.2 ml will contain 30769 cells.

So total number of cells per well will be 30769.

  

A student working in a hybridoma lab mixes the spleen and the mycloma cells, in a 2:1 ratio, and resuspends the fused cells with 23 mL of HAT. He/she then adds

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