Consider a memory of size 8KB 8192 bytes that allows dynamic

Consider a memory of size 8KB (8192 bytes) that allows dynamic, variable sized partitioning among processes and uses a linked list to keep track of free spaces (hereafter referred to as the free list) in the memory at any given time. Assume that there are 6 processes and assume that their memory size requirements (in bytes) are as given below:

P1: 500, P2: 600, P3: 1300, P4: 2000, P5: 100, P6: 200

Assume that the initial state of the free list is as shown below (BA is the base address and Sz is the size of each free space):

BA: 0; Sz: 1100 BA: 1200; Sz: 600 BA: 2000; Sz: 1800 BA: 6000; Sz 400

For these next questions assume the free list is in its initial state. Assume that the worst fit policy is used for partition placement. Identify the base address of the region to which each of the following processes will be allocated, assuming that they are allocated in the order specified and show the updated free list state after each allocation.

Note: If a partition cannot be allocated due to the state of the free list, simply type in the words cannot be accommodated as your answer.

Question 1: If P4 is allocated, what is the BA? _______

Question 2:

The updated free list is:

BA: _________ ; Sz: __________ BA: __________ ; Sz: ___________ BA: __________ ; Sz: __________ BA: _________ ; Sz ___________

Solution

BA: 0; Sz: 1100 BA: 1200; Sz: 600 BA: 2000; Sz: 1800 BA: 6000; Sz 400

Question 1: P4 cannot be allocated memory because there is not enough memory(2000) for P4 left after allocating memory to P1 and P2. Even p3 also cannot be allocated memory.

Question 2: After allocating memory to P1 and P2 using worst fit policy ,the updated free list is :

BA: 0 Sz: 1100 BA: 1200; Sz: 600 BA: 3100; Sz: 700 BA: 6000; Sz 400