2ln3 21n x 3 lny ln zSolutionsolution 2ln 32 ln x3ln y ln

Solution

solution

2(ln 3+2 ln x)-(3ln y +ln z)

=2 ln3+4 lnx- 3 ln y-ln z

= ln 3²+ln x⁴-ln y³- lnz

= ln 9+ln x⁴- ln y³ - ln z

ln 9= ln z+ ln y³- lnx^4

ln 9= lnz+(ln y³/x⁴)

ln9=ln z(y³/x⁴⁾

^{taking an}tilog

9 = y³z/x⁴

9x⁴=zy³

9x⁴-zy³=0