Complete a Punnett square to show the genotypes and phenotyp
Solution
1. Parents are Tt xTt
Gametes- T, t,T,t
Punnet square will be
Genotypic ratio is 1:2:1 and genotyes and phenotypes are TT - homozygous tall, Tt- heterozygous tall and tt- homozygous dwarf.
2.Heterozygous parents for brown eye right handedness will have the same genotype as BbRr.
Hence when these get married the following results will be obtained
Genotype of parents- BbRr xBbRr
Gametes - BR,Br,bR,br from each parent
Hence the punnet square can be shown as
Phenotypic ratio of the offsprings is 9:3:3:1 i.e; 9- Brown eyed right handed, 3- brown eyed left handed, 3- blue eyed right handed and 1- blue eyed lefthanded.
3.In chimpanzee straight fingers are dominant with \' F\' allel over bent fingers with \'f\' allel
Hence the genotype of heterozygour condition for straight fingers can be given as \' Ff\' and for homozygous bent fingers \'ff\'
Parents - Ff x ff
Gametes F,f and f,f
Punnet square can be shown as
The genotypes of the offsprings are Ff-2, ff-2 hence the genotypic ratio is 2:2
The phenotypes are heterozygous straight fingers-2 and homozygous bent fingers -2
Hence the phenotypic ratio is 2:2.
4.The genotype of red flower is RR, white flower is rr and pink flower is Rr.
The intercoss of pink flowers can be shown as follows
Parents - Rr x Rr
Gametes- R,r from each parent
Hence the punnet square can be shown as
Genotype of the offsprings are RR-1,Rr-2 and rr-1 hence the genotypic ratio is 1:2:1
Phenotypes are homozygous red flowers -1, heterozygous pink flowers-2,homozygous white flowers-1, hence the phenotypic ratio is 1:2:1.
| Gametes | T | t |
| T | TT | Tt |
| t | Tt | tt |

