Complete a Punnett square to show the genotypes and phenotyp

Complete a Punnett square to show the genotypes and phenotypes expected for the following cross: heterozygous tall x heterozygous tall In humans, the gene for brown eyes (b) is dominant to the gene for blue eyes and the gene for right handedness (r) is dominant to the gene for left handedness. Two individuals heterozygous for both of these characteristics marry. Complete a Punnett square to show the expected genotypes and phenotypes of the offspring. Summarize the ratio of the phenotypes In chimpanzees, straight fingers are dominant to bent fingers. Complete a Punnett square to show the genotypes and phenotypes expected for the following cross: heterozygous straight x homozygous bent In four o\'clock flowers, red plants are homozygous for the allele (R) of the gene for flower color. Plants with white flowers are homozygous for the (r) allele of the same gene. Plants with pink flowers are are heterozygous for these two alleles. Complete a Punnett square to show genotypes and phenotypes that are expected when plants with pink flowers are intercrossed.

Solution

1. Parents are Tt xTt

Gametes- T, t,T,t

Punnet square will be

Genotypic ratio is 1:2:1 and genotyes and phenotypes are TT - homozygous tall, Tt- heterozygous tall and tt- homozygous dwarf.

2.Heterozygous parents for brown eye right handedness will have the same genotype as BbRr.

Hence when these get married the following results will be obtained

Genotype of parents- BbRr xBbRr

Gametes - BR,Br,bR,br from each parent

Hence the punnet square can be shown as

Phenotypic ratio of the offsprings  is 9:3:3:1 i.e; 9- Brown eyed right handed, 3- brown eyed left handed, 3- blue eyed right handed and 1- blue eyed lefthanded.

3.In chimpanzee straight fingers are dominant with \' F\' allel over bent fingers with \'f\' allel

Hence the genotype of heterozygour condition for straight fingers can be given as \' Ff\' and for homozygous bent fingers \'ff\'

Parents - Ff x ff

Gametes F,f and f,f

Punnet square can be shown as

The genotypes of the offsprings are Ff-2, ff-2 hence the genotypic ratio is 2:2

The phenotypes are heterozygous straight fingers-2 and homozygous bent fingers -2

Hence the phenotypic ratio is 2:2.

4.The genotype of red flower is RR, white flower is rr and pink flower is Rr.

The intercoss of pink flowers can be shown as follows

Parents - Rr x Rr

Gametes- R,r from each parent

Hence the punnet square can be shown as

Genotype of the offsprings are RR-1,Rr-2 and rr-1 hence the genotypic ratio is 1:2:1

Phenotypes are homozygous red flowers -1, heterozygous pink flowers-2,homozygous white flowers-1, hence the phenotypic ratio is 1:2:1.

Gametes T t
T TT Tt
t Tt tt
 Complete a Punnett square to show the genotypes and phenotypes expected for the following cross: heterozygous tall x heterozygous tall In humans, the gene for
 Complete a Punnett square to show the genotypes and phenotypes expected for the following cross: heterozygous tall x heterozygous tall In humans, the gene for

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