A stone is launched vertically upward from a cliff 256 ft ab

A stone is launched vertically upward from a cliff 256 ft above the ground at a speed of 96 ft / s. Its height above the ground t seconds after the launch is given by s = - 16t2 + 96t + 256 for . When does the stone reach its maximum height? The stone reaches its maximum height at second(s).

Solution

when velocity is 0 v=u-at =96-32t v=0 t=3 s