28 You are given a box containing NH N2 and H2 at equilibriu
2.8. You are given a box containing NH, N2, and H2 at equilibrium at he contents are analyzed, and the following concentrations 1000 K. T are found: NH3-1.02 mol/L, N2-1.03 mol/L, and H2-1.62 mol/L. Calculate the value of K for the reaction: Nao + 3H 2NH3(g) 2(8) 2(8)
Solution
from equation,
AT equilibrium,
K = [NH3]^2/[N2][H2]^3
= 1.02^2/(1.03*1.62^3)
= 0.237
