261 mL of a 018 M sodium hydroxide solution is added to 326

261 mL of a 0.18 M sodium hydroxide solution is added to 326 mL of a 0.36 M rubidium hydroxide solution. Calculate the pH of the resulting solution of strong bases at 25 °C.

Solution

A/C to Total concentration (M) = M1V1+M2V2/V1+V2

M= 261X0.18+326X0.36/261+326

M= 46.98+117.36/587

Total concentration of OH- (M) = 0.279 M

pOH = -log(OH) =-log(0.279)= - (-0.55)= 0.55

pH=14-pOH

PH=14-0.55

PH= 13.45