Date Day Time Name 1 The pH of a 025 M NH solution was meas

Date Day & Time Name 1. The pH of a 0.25 M NH, solution was measured to be 11.33. Calculate Ken for NH answer

pH = 11.33

pH + pOH = 14

pOH = 14 - 11.33 = 2.67

pOH = -log[OH-] = 2.67

[OH-] = 2.14 x 10^-3 M

Keq equation,

NH3(aq) + H2O(l) <==> NH4+(aq) + OH-(aq)

Keq = [NH4+][OH-]/[NH3]

[NH4+] = [OH-]

[NH3] = 0.250 - [OH-] = 0.250 - 2.14 x 10^-3 = 0.24786 M

Keq = (2.14 x 10^-3)^2/(0.24786) = 1.85 x 10^-5