The acid dissociation constant for a weak acid HX at 25Solut

The acid dissociation constant for a weak acid HX at 25

Solution

Ka = 3.3x10^-8 = [H+][X-]/[HX]
assuming concentration as 1m
3.3x10^-8 = x^2 / 1
x = [H+] = [X-] = 1.82x10^-4 M

?G = ?G

The acid dissociation constant for a weak acid HX at 25Solution Ka = 3.3x10^-8 = [H+][X-]/[HX] assuming concentration as 1m 3.3x10^-8 = x^2 / 1 x = [H+] = [X-]

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site