230g 584g 0692 x 106 g QUESTION 16 iquld ammonia boilig poin

230g 58.4g 06.92 x 106 g QUESTION 16 iquld ammonia (boilig point -33.4*C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat 15.0g of NH3() from -55.0°C to-10.0°C specific heat, NH3 47ygK specific heat, NH3 2.2 J/g K heat of vaporization 23.5 kij/moll 2.15 k 037k) 21.5k 340 k 590 k QUESTION 17 S points A solution of 175 g of water and 106.1 g of an unkown solute has a frezing point of -3.3. Determine the molar mass of the unkown solute. Cick Save and Submit to save and submit. Click Save All Answers to sove all answers Save All Answers Save

Solution

To bring NH₃(l) at -55C to NH₃ (g) at temp -10C, following energies will be required

Energy required here would be = specific heat x change in temp. x amount of NH₃

= 4.7 j/g K x 21.6 x 15 g

= 1522.8 J or 1.52 kJ

Energy required here will be = heat of vaporisation x no. of moles of ammonia

= 23.5 kJ/mole x (15/18)

= 19.58 kJ

Energy required here would be = specific heat x change in temp. x amount of NH₃

= 2.2 j/g K x 23.4 x 15 g

= 772.2 j or 0.77 kJ

Total energy required would be = 1.52 + 19.58 + 0.77 = 21.87 kJ