C For an arbitrary class the lvalue operator method always e

C++: For an arbitrary class, the lvalue operator= method always ends with return *this while the lvalue copy constructor never does. Explain why operator= has the return statement while the copy constructor does not.

Solution

the Lvalue operator, \'=\', is the operator used for assignment. Like most other operators in C++, it can be overloaded.

The copy constructor operator, often just called the \"constructor operator\", is a special case of operator where the source and destination are of the same class type. It is one of the special member functions, which means that a default version of it is generated automatically by the compiler if the programmer does not declare one. The default version performs a memberwise copy, where each member is copied by its own copy assignment operator

The copy assignment operator differs from the copy constructor in that it must clean up the data members of the assignment target whereas the copy constructor assigns values to uninitialized data members.

C++: For an arbitrary class, the lvalue operator= method always ends with return *this while the lvalue copy constructor never does. Explain why operator= has t

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