A person invested 7500 for 1 year part at 5 part at 10 and t

A person invested $7500 for 1 year, part at 5%, part at 10%, and the remainder at 14% The total annual income from these investments was $851. The amount of money invested at 14% was $300 more than the amounts invested at 5% and 10% combined Find the amount invested at each rate. The person invested $ at 5%, 5 at 10%, and $ at 14%

Solution

amt invested at 5% be x

amt invested 10% be y

amt invested at 14% be z

x+y +z = $ 7500 -----(1)

0.05x +0.1y +0.14z = $ 851 ----(2)

z - (x+y) = 300 ---(3)

Solve the three equations:

x = $ 1100 ; y = $ 2500 ; z = $ 3900