Given CBA theta 25 degree c 36 b 1544 find ACB 98 degree

Given CBA = theta = 25 degree, c = 36, b = 15.44, find ACB 98 degrees 80.19 degrees 65 degrees no answer

Solution

angle CBA = 25 degrees

applying law of sines

15.44 / sin 25 = 36 / sin C

sin C = 36 / 36.5341

C = sin^-1 ( 36 / 36.5341 )

C = 80.19

angle ACB = 80.19 degrees

option 2 is correct