Claire wants to fence in a rectangular plot of land along a
Solution
Let the length of the rectangular garden be x feet and let its width be y feet. Since p feet of fencing extends along three sides ( length +2*width), we have x+2y = p or, y = (p-x)/2. Further the area of the rectangular garden is length *width = x*y = x*(p-x)/2 = -x2/2 + px/2. We know that A will be maximum when dA/dx = 0 and d2A/dx2 is negative. Here, dA/dx = -x +p/2 which is zero when x = p/2. Also, d2A/dx2 = -1 is negative regardless of the value of x. Hence the area of the rectangular garden will be maximum when x = p/2. Then theis maximum area is x*(p-x)/2 = p/2(p-p/2)/2 = (p/2)*p/2 *1/2 = p2/8. Option D is the correct answer.

