The terminal side of theta lies on the given line in the spe
     The terminal side of theta lies on the given line in the specified quadrant. Find the values of the six trigonometric functions of theta by finding a point on the line.  sin theta =  cos theta =  tan theta =  csc theta =  sec theta =  cot theta =   
  
  Solution
3x - y = 0
in quadrant 3 both x and y are negative
so lets find a point that lies on the line by picking a value for x
let x = -1
y = 3(-1) = -3
finding hypotenuse
h^2 = (-1)^2 + (-3)^2
h = sqrt 10
sin theta = perpendicular / hypotenuse = -3/ sqrt 10 = - 3 sqrt 10/ 10
cos theta = base / hypotenuse = -1 / sqrt 10 = -sqrt 10 / 10
tan theta = perpendicular / base = -3 / -1 = 3
csc theta = 1/ sin theta = - sqrt 10 /3
sec theta = 1 / cos theta = -sqrt 10
cot theta = 1/ tan theta = 1/3

