voltage necessary that ould be used tu plte u 7 Design an el

voltage necessary that ould be used tu plte u 7. Design an electroplating cell and calculate the minimum following: a. Silver b. Chromium

7. Designing an electroplating cell

a. Silver

Ag+(aq) + e- <==> Ag(s) Eo = 0.80 V

we need another half-cell with lower potential than silver

Cu2+ + 2e- <==> Cu(s) Eo = 0.34 V

Here, lower cell potential Cu would act as an anode and Ag would act as a cathode

So combining the two would give us,

2Ag+(aq) + Cu(s) <==> 2Ag(s) + Cu2+(aq)

Eocell = 0.80 - 0.34 = 0.46 V

Therefore, minimum voltage necessary to deposite Ag = 0.46 V

b. chromium

Cr3+(aq) + 3e- <==> Cr(s) Eo = -0.74 V

we need another half-cell with lower potential than chromium

Al3+ + 3e- <==> Al(s) Eo = -1.66 V

Here, lower cell potential Al would act as an anode and Cr would act as a cathode

So combining the two would give us,

Cr3+(aq) + Al(s) <==> Cr(s) + Al3+(aq)

Eocell = -0.74 - (-1.66) = 0.92 V

Therefore, minimum voltage necessary to deposite Ag = 0.92 V