A random variable x has density function given by fx2e2x x0
A random variable x has density function given by f(x)={2e^-2x x=>0, 0 x<0} the expected value and variance of x are =1/2 =1/4 respectively, a)find p(|x-|>1) b)use chebyshev\'s inequality to obtain an upper bound on (P|x-|>1)
Solution
a)
P( x - miu > 1 )
P( z > (1 - 1/2 / 1/4 )
P( z > 2 ) = 0.0228
