Find the length of the arc of the curve y2 x2 6y 4x 9 0
Find the length of the arc of the curve y^2 + x^2 - 6y - 4x + 9 = 0 from the point
(0, 3) to the point (2, 5).
(0, 3) to the point (2, 5).
Solution
y^2 + x^2 - 6y - 4x + 9 = 0
y2-6y+9=4x-x2
(y-3)2=4x-x2
y=3+(4x-x2)
y\'=(4-2x)/2(4x-x2)
ds=int(0,2)(1+{y\'}2)=[1+(4-2x)2/4(4x-x2)]
integrate and get your ans
