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Edit View History Bookmarks Window Help ALEKS luth Martinez Lean STOICHIOMETRY Identifying the limiting reactant in a drawing of a mixture The drawing below shows a mixture of molecules: key o gcarbon hydrogen O nitrogen sulfur oxygen O chlorine Suppose the following chemical reaction can take place in this mixture CH 4(g)+ 202(g) CO 2(g)+ 2 H2O(g) of which reactant are there the most initial oles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula: Explanation Check MacBook Pro : 0

Solution

From the drawing,

Number of moles of O2= 6 (most initial moles)

Number of moles of CH4= 4 (least initial moles)

From stoichiometry of reaction,

1 mole of CH4=2 Mole of O2

4 mole of CH4 = x mole of O2

x=4*2 = 8 mole of O2

but supplied mole of O2=6

therefore, O2 is limiting reactant.