Explain why a line in R3 that does not pass through the orig
Explain why a line in R^3 that does not pass through the origin is not a vector space by exhibiting a vector space axiom that is not satisfied.
Solution
A line \'L\' is a set of points
So let V={(x,y,z)/ (x,y,z) is a point on the line L}
To say that V is a vector space (V, +) should be an abelian group
But the identity element is (0,0,0) with respective to \'+\'
Because we are given a line which \'L\' do not passes through origin, (0,0,0) is not a point in V
I.e., V has no identity element and hence can not be a group
Thus V is not a vector space.
Therefore a line that donot pass through the orign can not be a vector space.
