Cleveland Ohio and Jacksonville Florida lie approximately on

Cleveland, Ohio, and Jacksonville, Florida, lie approximately on the same meridian. Cleveland has a latitude of 41.5 degree N, and Jacksonville has a latitude of 30.3 degree N. Find the distance between these two cities. (The radius of the earth is 3960 mi. Round your answer to the nearest mile.) 38.119 mi

Solution

circumference of earth is 2* pi * r

= 2 * 3.14 * 3960

= 24868.8

cleveland has latitude of 41.5

jacksonville has latitude of 30.3

angle between two cities is difference in their latitude

difference of latitude = 41.5 - 30.3 = 11.2

distance between 2 cities is

s = 11.2 / 360 *  24868.8

s = 773.696

distance = 774 miles