Two sides of a triangular lot measure 56 feet by 74 feet and

Two sides of a triangular lot measure
56 feet by 74 feet and the angle between these two sides is 74°.
Find the area of the lot. (round to the nearest whole number as needed)

Solution

Area of triangle = (product of sides/2) sin(including angle)

area=(56*74/2)sin 74 degree= 2072 sin74=1992 feet²