15 4 Find the value of the unknown quantity Po that establis
Solution
Rate of interest = 20%
1. Convert the linear gradient series into uniform series and then calculate the PW of the uniform series.
Take A1 (inflow in the first years) = 1400
Gradient (decreasing) = 300
Number of years = 3
A = A1 – G (A/G, 20%, 3)
A = 1400 – 300 (A/G, 20%, 3)
A = 1400 – 300 (0.8791)
A = 1136
PW of uniform series 1018 at the 0th year
PW = 1136 (P/A, 20%, 3)
PW = 1136 (2.1065) = 2393------------------------------------------- (1)
2. Calculate the present worth of 500 for 5 years (4th, 5th, 6th, 7th & 8th) at the end of 3rd year
PV at 3rd year = 500 (P/A, 20%, 5)
PV at 3rd year = 500 (2.9906) = 1495
Bring the above single amount to the 0th year by using single payment factor.
PW of 1495 at 0th year = 1495 (P/F, 20%, 3)
PW of 1495 at 0th year = 1495 (0.5787) = 865 ------------------ (2)
3. PW 2000 of the 10th year by using single payment factor
PW = 2000 (P/A, 20%, 10)
PW = 2000 (0.1615) = 323 ------------------------------------------- (3)
Total Present Value at 0th year = 2393 + 865 + 323 = 3581
