Reattempt this question Question with last attempt is displa
Solution
distance from vertical diameter =x =rcos,distance from horizontal diameter =y =rsin
for 1 rotation 0 <2
given bug sits 9.8inches from center of rotation. so r =9.9 inches
=>x=9.9cos
(a)
right of vertical diameter for the second time=> bug is in 4th quadrant
9.9cos = 4.1
=> =2 -cos-1(4.1/9.9)
distance bug travelled =r
distance bug travelled =9.9*(2 -cos-1(4.1/9.9)) inches exactly
distance bug travelled =50.88 inches approximately
(b)
left of vertical diameter for the first time=> bug is in 2nd quadrant
9.9cos = -5.7
=> = -cos-1(5.7/9.9)
distance bug travelled =9.9*( -cos-1(5.7/9.9)) inches exactly
distance bug travelled =21.625 inches approximately
(c)
left of vertical diameter for the second time=> bug is in 3rd quadrant
9.9cos = -6.4
=> = +cos-1(6.4/9.9)
distance bug travelled =9.9*( +cos-1(6.4/9.9)) inches exactly
distance bug travelled =39.694 inches approximately
===========================================================
please rate if helpful. please comment if you have any doubt

