Lab Spring18LEE Activities and Due Dates Rec D Quantitative
Solution
Ans. #1. Moles of NaCl = Mass / Molar mass
= 25.1 g / (58.442468 g/ mol)
= 0.4295 mol
#2. Moles of CS2 = Mass / Molar mass = 64.7 g / (76.143 g / mol) = 0.84972 mol
# Number of CS2 molecules = Moles of CS2 x Avogadro number
= 0.84972 mol x (6.022 x 1023 molecules / mol)
= 5.1170 x 1023 molecules
# 1 molecule of CS2 consists of 3 atoms – (1 C-atom + 2 S-atom)
So,
Total number of atoms = (3 atoms / molecule) x number of CS2 molecules
= (3 atoms / molecule) x (5.1170 x 1023 molecules)
= 1.5351 x 1024 atoms
#3. The three types of information required are-
A. The number of isotopes that exist for the element
C. The percentage abundance of each isotope
E. The masses of the isotopes on the carbon-12 scale.
# The average atomic mass of an element can be given as follow-
Average atomic mass = (% xA x its atomic mass) + (% yB x its atomic mass) + so on
Where, x = Atomic mass of xA isotope ; , y = Atomic mass of yA isotope and so on.
% = % abundance of the respective isotopes
Atomic mass of an isotope is on the relative scale of C-12 mass scale.
