What is the emf of a galvanic cell consisting of a Cd2Cd hal

What is the emf of a galvanic cell consisting of a Cd2+/Cd half-cell and a Pt/H+/H2 half-cell if [Cd2+] = 0.27 M, [H+] = 0.18 M, andPH2 = 0.76 atm?

Solution

Cd + 2H+ ---> Cd2+ + H2 Eo(cell) = + 0.40 V

E(cell) = Eo(cell) - (0.0592/n)log Q
E(cell) = 0.40 V - (0.0592/2)log([Cd2+]P(H2)/[H+]^2
E(cell) = 0.40 V - 0.0167 V = 0.39832V

 What is the emf of a galvanic cell consisting of a Cd2+/Cd half-cell and a Pt/H+/H2 half-cell if [Cd2+] = 0.27 M, [H+] = 0.18 M, andPH2 = 0.76 atm?Solution Cd

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