Using the matrix A 1 2 1 1 1 2 2 1 2 4 0 6 and the column v
Using the matrix A =
1 2 1 1
1 2 2 -1
2 4 0 6
and the column vector b =
7
12
4
(a) State the rank of A. Is the column space of A a line, a plane, or all of R^3 ? Justify your answer.
(b) Find the general solution to the system Ax = b.
Solution
Let B = [ A| b] =
1
2
1
1
7
1
2
2
-1
12
2
4
0
6
4
We will reduce B to its RREF as under:
Add -1 times the 1st row to the 2nd row
Add -2 times the 1st row to the 3rd row
Add 2 times the 2nd row to the 3rd row
Add -1 times the 2nd row to the 1st row
Then the RREF of B is
1
2
0
3
2
0
0
1
-2
5
0
0
0
0
0
(a) Thus, the rank of A is 2 and only the vectors (1,1,2)T and (1,2,0)T are linearly independent. The other two columns of A are linear combinations of these two columns. . The column space of A is a plane spanned by its 1st and 3rd columns.
(b) If X = (x,y,z,w)T , then the equation AX = b is equivalent to x +2y +3w = 2 and z-2w = 5. Let y = r and w = t. Then x = 2- 2r-3t and z = 5+2t so that X = (2- 2r-3t, r, 5+2t,t)T = (2,0,5,0)T + r (-2,1,0,0)T +t (-3,0,2,1)T
| 1 | 2 | 1 | 1 | 7 | 
| 1 | 2 | 2 | -1 | 12 | 
| 2 | 4 | 0 | 6 | 4 | 


