Given a convex set C argue that a point x elementof C is ext
Solution
Firstly, let xC be an extreme point. Then, by definition,
u,v C, uv, such that x = (1-p)u+pv ; p(0,1) - (1)
We need to show that C\\{x} is a convex set.
Let m,n C\\{x}. Then, m,nx.
Also, as C\\{x}C, m,nC.
=> (1-p)m+pn C, since C is convex.
=> (1-p)m+pn C\\{x}, by (1). [ Reason: If (1-p)m+pn=x, then it would contradict the fact that x is an extreme point.]
Therefore, C\\{x} is a convex set.
Conversely, let C\\{x} be a convex set.
We need to show that x is an extreme point. Let,on the contrary, x not be an extreme point.
Then, since C is convex,
m,nC such that x= (1-p)m+pn; p(0,1) -(2)
Note that m,n C\\{x}, which is convex.
=> (1-p)m+pn C\\{x} ; p(0,1)
=> x C\\{x}, by (2), which is a contradiction.
Thus, x is an extreme point.
Hence proved.
