Solve the triangle for the remaining angles and sides If no
Solution
a= 4 ; b = 1 ; C = 100 deg
Use cosine rule : c^2 = (a^2 +b^2 -2abcosC)
= 16 + 1 - 8cos100
= 10.10
c = 3.178
use sine rule : a/sinA = c/sin100
sinA = 4*sin100/3.178 = -0.637
Now sin is -ve in IIIrd qudarnt .So , A > 180
So, no triangle possible
