FIND AN EQUATION OF THE TANGENT LINE TO THE GRAPH OF THE FOL

Solution

f(x) = -3x² + 2

First, the slope of the tangent line at (-3,-25) is given by

first finding the derivative.

f\'(x) = -6x

the slope is f\'(x) evaluated at x = -3.

m = -6*-3 = 18

The equation of the tangent line can be gotten by using the

point slope version of a linear function:

y - (-25) = 18(x - (-3))

y + 25 = 18(x + 3)

y = -25 + 18x + 54

y = 18x + 29

Which is your final answer.