Ques 4 httppuushoS2nI424ce17f71pngSolutiona Plurality with E

Ques 4

http://puu.sh/oS2nI/424ce17f71.png

Solution

a>

Plurality with Elimination is carried out in rounds. After each round of voting the candidate (or alternative) with the fewest first place votes is eliminated and a new round of voting is done with the remaining candidates. When only two candidates remain in a round, the candidate with the most votes wins the election. For an N candidate election, the Method of Plurality with Elimination requires N-1 rounds

for round 1

A got 120 votes

B got 84+48 = 132 votes

C got 96 votes

So in this round C gets eleminated as C gets the least first place votes.

now we are letf with just two options A and B that is for first and second place.

all the C are eleninated and the ones below C in the table will move up and replace the C\'s

so for the last round we could see that A gets 120 + 96 = 216 votes and

B gets = 84+48 = 132 votes hence

A is the winner of the straw vote.

b>

A gets 120+48 first votes = 168 votes

B gets = 84 first place votes

C gets = 96 first place votes

so B get eleminated

now in the last round we are left with A and C

all the B are eleninated and the ones below B in the table will move up and replace the B\'s

and since A gets 120 + 48 = 168 frst place votes

and C gets = 96 + 84 = 180 first place votes

hence C is the winner