The area of a rectangle is 63 yd2 and the length of the rect

The area of a rectangle is 63 yd^2 and the length of the rectangle is 11 yd more than twice the width. Find the dimensions of the rectangle.

Area of rectangle = L*W = 63 yd^2

also given that

L = 11 + 2W

Solving both equation:

(11 + 2W)*W = 63

11W + 2W^2 = 63

2W^2 + 11W - 63 = 0

Solving the qudratic equation:

W = [-(11) +/- sqrt (121 + 4*2*63)]/(2*2)

W1 = 3.5 yd

W2 = -9 yd, since width cannot be negative,

width of rectangle = 3.5 yd

Length = 11 + 2*3.5 = 18 yd