The answer is 660 lbs I just want to know how to get this an

384 A roller 2 ft in diameter weighs 1000 lb. What horizontal force through the center of the roller is needed to pull the roller over a stationary brick 2 inches high?

Solution

According to the given problem,

The vertical height from the edge of the brick to the center is 22 inches. The horizontal distance from the edge of the brick to the center of gravity requires some calculation.

From the brick edge to the center is 24 inches. sketch a horizontal line frm the edge of the brick to the vertical downward radius.

Now have a triangle, 24 hypotenuse, 22 on the downward leg, and the horizontal leg will be

d = 24²-22²)

d = 9.6m approx.

Now moments around the edge sum to zero.

F*22 - weight*9.6=0
Force at center=1000lbs*9.6/22 = 450lbs

At the top, the process is similar.

Force*46-1000*9.6 = 0

Force at the top = 210lbs

Total force is ,

F = 210+450 = 660lbs