A geneticist who uses a carnivorous picther plant as a model
A geneticist who uses a carnivorous picther plant as a model plant makes the following corss. she proceeds to take a wild type pure-breeding female pitcher trisomic for chromosome 2 and crosses it to a normal dipoloid male picther plant that is homozygous for a recissive mutation (v) that makes it hungry all the time (the super hungry mutant). A trisomic F1 plant is then back-crossed to the super-hungry male parent. From this cross:
a) what is the ratio of the normal pitcher plants to those that are super hungry when you assume that v is located on chromosome 2?
b) what is the ratio of normal pitcher plants to those that are super hungry when you assume that v is located on chromosomes 2?
Solution
Answer:
a). 1:1
Explanation:
VV+1 (wild) x (super hungry plant) vv---Parents
V, V+1 v -----------------------------Gametes
Vv (wild), V+1v (trisomic wild)-----F1
V+1v x vv-----------Back cross
v
V+1
V+1 v (50%)
v
vv (50%)
The normal pitcher plants are 50% and super hungry plants are 50%.
Normal (1) : Super hungry pitcher plants (1)
| v | |
| V+1 | V+1 v (50%) |
| v | vv (50%) |
