A Solve the following initial value problem t2 22t 96 dydt

A. Solve the following initial value problem: (t^2 - 22t + 96) dy/dt = y with y(11) = 1. (Find y as a function of t.) y = On what interval is the solution valid? Answer: It is valid for Find the limit of the solution as t approaches the left end of the interval. (Your answer should be a number or the word \"infinite\".) Answer: Similar to C, but for the right end. Answer:

Solution

10y=(t-16)/(t-6)+9