In C only use include and please show your output For this a

In C++

only use #include <iostream>

and please show your output

For this assignment you will implement a dynamic array. You are to build a class called MyDynamicArray. Your dynamic array class should manage the storage of an array that can grow and shrink. The public methods of your class should be the following:
MyDynamicArray(); Default Constructor. The array should be of size 2.
MyDynamicArray(int s); For this constructor the array should be of size s.
~MyDynamicArray(); Destructor for the class.
int& operator[](int i); Traditional [] operator. Should print a message if
i is out of bounds and return a reference to
a zero value.
void add(int v); increases the size of the array by 1 and
stores v there.
void del(); reduces the size of the array by 1.
int length(); returns the length of the array.
int clear(); Frees any space currently used and starts
over with an array of size 2.

The output should be:

Doubling to : 4
Doubling to : 8
Doubling to : 16
Doubling to : 32
Doubling to : 64
Doubling to : 128
The sum is : 4950
Reducing to : 64
Reducing to : 32
Reducing to : 16
Out of bounds reference : 60
Doubling to : 20
Doubling to : 40
Doubling to : 80
Doubling to : 160
Doubling to : 320
The sum is : 20185
Reducing to : 160
Reducing to : 80
Reducing to : 40
Out of bounds reference : 60
Doubling to : 80
Doubling to : 160
Doubling to : 320
The sum is : 20195

This is the sample main file:

#include <iostream>
using namespace std;
#include \"MyDynamicArray.cpp\"
int main() {
MyDynamicArray x;
for (int i=0; i<100; i++){
x.add(i);
}
int sum = 0;
for (int i=0; i<x.length(); i++){
sum+=x[i];
}
cout << \"The sum is : \" << sum << endl;
for (int i=0; i<95; i++)
x.del();
x[60] = 27;
MyDynamicArray y(10);
for (int i=0; i<y.length(); i++) y[i] = i*i;
for (int i=0; i<200; i++){
y.add(i);
}
sum = 0;
for (int i=0; i<y.length(); i++){
sum+=y[i];
}
cout << \"The sum is : \" << sum << endl;
for (int i=0; i<195; i++)
y.del();
y[60] = 27;
for (int i=0; i<200; i++){
y.add(i);
}
sum = 0;
for (int i=0; i<y.length(); i++){
sum+=y[i];
}
cout << \"The sum is : \" << sum << endl;
}

Solution

// your output and question do not match so doing as per output
# include <iostream>
using namespace std;

class MyDynamicArray
{
private:
int *arr;
int siz;
int length_a;
  
public:
MyDynamicArray(int s)
{
arr = new int[s];
length_a = s;
siz = 0;
}

MyDynamicArray()
{
arr = new int[2];
length_a = 2;
siz = 0;
}

~MyDynamicArray()
{
//delete [] arr;
}

int& operator[](int i)
{
if (i >= siz)
{
cout << \"Out of bounds reference : \" << i <<endl;
int y = 0;
int& a = y;
return a;
}
  
return arr[i];
}

void add(int v)
{
if (siz < length_a)
{
arr[siz] = v;
siz =siz+1;
}
else
{
cout << \"Doubling to : \" << 2*length_a <<endl;
int *a = new int[2*length_a];
//memcpy( a, arr, siz * sizeof(int) );

  
for (int i = 0; i < siz; i++)
{
a[i] = arr[i];
}
length_a = 2*length_a;
delete [] arr;
arr = a;
arr[siz] = v;
siz = siz+1;
}
}

void del()
{
if (siz > 0 && length_a > 0)
{
if (siz - 1 < length_a/2)
{
cout << \"Reducing to : \" << length_a/2 << endl;
int *a = new int[length_a/2];
for (int i = 0; i < siz -1; i++)
{
a[i] = arr[i];
}
length_a = length_a/2;
siz--;
delete [] arr;
arr = a;
}
else
{
siz--;
}
}
}

int length()
{
return siz;
}

int clear()
{
delete [] arr;
arr = new int[2];
siz = 0;
length_a = 2;
}
};