QUESTION3 05 p KOtBu Which starting material below would be

QUESTION3 0.5 p KOtBu Which starting material (below) would be the best option to fill in the box above? (Ie., which starting material would produce the alkene shown in the highest yield?) Br CI QUESTION 4 If the solvent in the reaction below is changed to a polar aprotic solvent, how will the reaction rate be affected? KCI CH3OH The reaction rate will increase The reaction rate will decrease

Solution

for question3  

KOtBu abstracts H+ from less hindered carbon , hence halide should be on more hindered side of double bond

Hence we have two options A , B

Out of F , Br we have Br good leaving group making reatcion efficient , hence answer is option B

4) we had substitution at primary carbon. hence its SN2 mechanism

Polar aprotic solvent is more suitable for sn2 reactions compared to polar protic solvents like CH3OH

Hence when we replace CH3OH with polar aproctic solvent The reaction rate increases