Part A Calculations for Solution Preparation d Calculate the

Part A: Calculations for Solution Preparation d. Calculate the mass of solid malonic acid (CH(COOH)2) necessary to prepare 50.0 mL of a 0.15 M (CH2(COOH)2) solution. b. Calculate the mass of solid manganese sulfate monohydrate (MnSO4 H2O) necessary to prepare 50.0 mL of a 0.020 M manganese ion (Mn *).

Solution

Ans :

Molarity = no. of moles of solute / volume of solution in L

a) M = n / V

0.15 = n / 0.050

n = 0.0075 mol

Mass of malonic acid = 0.0075 x molar mass

= 0.0075 x 104.0615

= 0.78 grams

b) M = n / V

0.020 = n / 0.050

n = 0.001 mol

mass of manganese sulfate monohydrate = 0.001 x molar mass

= 0.001 x 169.0159

= 0.169 grams