please show steps im very confuse about this problem thank D

please show steps, im very confuse about this problem, thank!

Dr. Jenkins built a large wind chime as a Christmas gift. The steel pipes used are 3.50 in n diameter with a wall thickness of 0.20 in., and the support pin is .250 in. diameter. For a 55 lb. chime, supported at the midpoint of the .250 in. pin, calculate the maximum average shear stress acting on the pin. Chimes are usually supported with a cross pin located at 22.4 of the pipe length, but some choose to support at the very end as shown in the drawing. If the design shear strength of the steel pipe is 18 ksi, find the minimum safe distance b from the pin to the end of the pipe to avoid failure by shearing along the dotted planes indicated in the drawing.

Solution

Shear stress average = Applied force / area.

Or

Shear stress ave.= F/(2r2)

Or

Shear stress ave.= 4F/(2d2).

Here d is the diameter of the pin.

Bearing stress equation:

Bt= F/(2td) ( t = thickness of wall is given).

Given load or applied force as 55lb.

i.e. 0.45×55 kg ×9.81 = 242.8 N.

Apply these equations, take it easy don\'t be confuse.

please show steps, im very confuse about this problem, thank! Dr. Jenkins built a large wind chime as a Christmas gift. The steel pipes used are 3.50 in n diame

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