math statistics probability Question 3 15 points Let ZGeomet
math statistics, probability Question 3
Solution
Defination of Geometric distribution :
It’s the probability that the first occurrence of success requires k number of independent trials, each with success probability . If the probability of success on each trial is , then the probability that the kth trial (out of k trials) is the first success is
P( Z = k ) = ( 1 - ) k-1
for k = 1, 2, 3, ....
Now,
Given problem
Let Z - Geometric () , compute P(5 Z 9)
for this we need to find
P ( 5<=Z<=9) = P(Z=5)+P(Z=6)+P(Z=7)+P(Z=8)+P(Z=9)
Here,
P(Z=5) = ( 1 - ) 5-1 = ( 1 - ) 4 , P(Z=6)= ( 1 - ) 6-1 = ( 1 - ) 5
P(Z=7)=( 1 - ) 7-1 = ( 1 - ) 6 , P(Z=8) = ( 1 - ) 8-1 = ( 1 - ) 7 ,
P(Z=9)= ( 1 - ) 9-1 =( 1 - ) 8
Therefore,
P ( 5<=Z<=9) = P(Z=5)+P(Z=6)+P(Z=7)+P(Z=8)+P(Z=9)
=( 1 - ) 4 + ( 1 - ) 5 + ( 1 - ) 6 + ( 1 - ) 7 + ( 1 - ) 8
