Proofs to Grade Problems with this title ask you to analyze
Proofs to Grade. Problems with this title ask you to analyze an alleged proof
of a claim and ask you to give it one of three grades. Assign a grade of A if the
claim and proof are correct, even if the proof is not the simplest or the proof
you would have given. Assign an F if the claim is incorrect, if the main idea
of the proof is incorrect or if most of the statements in it are incorrect. Assign
a C partial credit for a proof that is largely correct, but contains one or two
incorrect statements of justi.cations. Whenever the proof is incorrect, explain
your grade. Tell what is incorrect and why.
1. Claim. If m2 is odd, then m is odd.
\"Proof.\" Assume m is odd. Then m = 2k + 1 for some integer k. Then
m^2 = (2m + 1)^2 = 4m^2 + 4m + 1 = 2(2m^2 + 2m) + 1,
which is odd. Therefore, if m^2 is odd, then m is odd.
2. Claim. For every function f : R --> R, if f has relative minimum or
maximum at x = 0, then f\'0(0) = 0..
\"Proof..The derivative at a relative minimum or maximum must be zero.
3. Claim. If t is an irrational number then 5t is irrational.
\"Proof.\" Assume 5t is rational. Then 5t = p/q where p and q are in-
tegers, q 6= 0. Then t = p/5q which is rational. But t is irrational.
Solution
1) The first claim is true
Reason: Let us consider an even number which will be of the form m = 2p
m^2 = 4p^2, which will be even
m = 2p + 1
m^2 = (2p+1)^2 = 4p^2 + 2p + 1 = 2(2p^2+p) + 1. which is an odd number
Hence the claim is correct
2) Claim is False
Consider the function f(x) = |x|, which has relavtive minimum at x=0, but the derivative doesn\'t exist at that point
Hence the claim is false
3) Claim is true
Since the natural number * irrational number will be irrational, hence the claim is correct
