The null hypothesis and the alternate hypothesis are H0 The

The null hypothesis and the alternate hypothesis are: H_0. The frequencies are equal. H_1. The frequencies are not equal. State the decision rule, using the 0.01 significance level. Compute the value of chi-square.

Solution

Degrees of freedom = 3

chi square at 0.01 sign level =11.345

Reject H0 if chi square > 11.345

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b)

cHI SQUARE = 6

Decision: Accept null hypothesis that all frequencies are equal

Category	f0	Expected	O-E	(O-e)^2/E
A	10	12.5	-2.5	0.5
B	10	12.5	-2.5	0.5
C	20	12.5	7.5	4.5
D	10	12.5	-2.5	0.5
	50	50	0	6