Data Transmission Calculations for Ayschronous and Synchronu

Data Transmission Calculations for Ayschronous and Synchronuos connections

Question 5 (3 points)

A file size of eleven (11) Megabytes is transmitted from one computer to another computer on a local area network using Ethernet protocol (IEEE 802.3). The protocol converts the data to data frames using the frame structure shown below.

How many frames are needed to transmit the file? Note 1 MB =1024*1024 bytes

The answer is an integer number; like 1000, 3500, or 4891.

The Frame Structure of IEEE 802.3 used for this problem

    
        
        
        
        
        
        
        
    

            

Preamble

            

7 bytes

        

Start
            

1 byte

        

Destination address
            

6 bytes

        

Source address
            

6 bytes

        

Data length
            

2 bytes

        

Frame Data
            

1468 bytes

        

Checksum
            

4 bytes

        

Question 6 (3 points)

In problem 5, what is the overhead of one frame in bytes? The number must be integer. Do not put anything else after the number.

Question 7 (4 points)

In problem 5, calculate the overall overhead for this data transmission. Show your work clearly.

Question 8 (8 points)

In problem 5, calculate the time (in seconds) needed to complete the file transmission between the two computers if the speed of data transmission is set at 10 Mbps. Clearly show your work. Round your answer to two decimal places.

Preamble              7 bytes

Start              1 byte

Destination address              6 bytes

Source address              6 bytes

Data length              2 bytes

Frame Data              1468 bytes

Checksum              4 bytes

A file size of eleven (11) Megabytes s transmitted from one computer to another computer on a local area network using Ethernet protocol (IEEE 802 3) The protocol converts the data to data frames using the frame structure shown below How many frames are needed to transmit the file? Note 1 MB =1024*1024 bytes the answer is an integer number; like 1000. 3500. or 4891. The Frame Structure of IEEE 802.3 used for this problem in problem 5. what is the overhead of one frame in bytes? The number must be integer Do not put anything else after the number in problem 5. Calculate the overhead over head for this data transmission Show your work dearly in problem 5. calculate the time (in seconds) needed to complete the file transmission between the two computers if the speed of data transmission is set at 10 Mbps Clearly show your work.

Solution

1.

1MB=1024*1024 bytes

11MB=11*1024*1024= 11534336 bytes

Number of frames required= filesize/ data size which can be transmitted in one frame

=11534336/1468

=7857 frames

2.

overhead of 1 frame= framesize- data size which can be transmitted in one frame

=1494-1468

=26 bytes

total overhead for transmitting 11MB= no of frames required to transmit 11MB * overhead in frame

=7857 *26

=204282 bytes

3.

10 Megabits= 1310720 bytes

11 Megabytes =11534336 bytes

the link has speed of 10 Megabits per sec

if it requires 1 second to transmit 10 Megabits then it will require 11534336/1310720 secs= 8.80 secs to trasnmit

11534336 i.e 11MB