For a gaseous reaction standard conditions are 298 K and a p
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction
2N(g) + 3H2(g) <===> 2NH3(g)
the standard change in Gibbs free energy is ?G ° = -69.0 kJ/mol. What is ?G for this reaction at 298 K when the partial pressures are
PN2 = 0.100 atm, PH2 = 0.150 atm, and PNH3 = 0.700 atm
Solution
Kp = p^NH3/p^3 H2 x pN2 = 0.7^2/(0.1x0.15^3) = 1451.85,
Kc = Kp/RT^dn = Kp/(RT)^-2 = Kp x(RT)^2 = 1451.85 x(0.0821x298)^2 = 869041 ,
dG = dGo-RTln Kc
= -69000 -(8.314x298 ln(869041))
= -102.88 KJ/mol
