Question 15 of 20 Avail Due Point Grad Desc Polici You You Y
Question 15 of 20 Avail Due Point Grad Desc Polici You You You The 100 Map Sapling Learning 100 100 If the Kb of a weak base is 4.0 x106, what is the pH of a 0.23 M solution of this base? Number 100 pH = 100 eTe He 0 Owe 100
Solution
XOH + H2O <===> OH-(aq) + X+ (aq) Kb of XOH = 4.0 x 10-6
Kb = [OH-][X+] / [XOH]
[OH-] = [X+]
Kb = [OH-]2 / [XOH]
[OH-]2 = Kb x [XOH] => 4.0 x 10-6 x 0.23 => 9.2 x 10-7
[OH-] = 9.59 x 10-4 M
pOH = - log (9.59 x 10-4 ) => 3.02
pH = 14 - 3.02 => 10.98
Answer = 10.98
