Solve log3x 12 log3x 4 2Solutionlog3x12 log3x4 2 use the

Solution

log3(x+12) +log3(x+4) =2

use the property : logx +logy = log(x*y)

So, log3(x+12)(x+4) = 2

(x+12)(x+4) = 9

x^2 +16x +48 =9

x^2 +16x + 39 =0

factorise : x^2 +13x +3x +39 =0

x(x+13)+ 3(x+13)=0

(x+3)(x+13) =0

x= -3 , x=-13